3.1.15 \(\int x \cosh ^{-1}(a x)^2 \, dx\) [15]

Optimal. Leaf size=64 \[ \frac {x^2}{4}-\frac {x \sqrt {-1+a x} \sqrt {1+a x} \cosh ^{-1}(a x)}{2 a}-\frac {\cosh ^{-1}(a x)^2}{4 a^2}+\frac {1}{2} x^2 \cosh ^{-1}(a x)^2 \]

[Out]

1/4*x^2-1/4*arccosh(a*x)^2/a^2+1/2*x^2*arccosh(a*x)^2-1/2*x*arccosh(a*x)*(a*x-1)^(1/2)*(a*x+1)^(1/2)/a

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Rubi [A]
time = 0.16, antiderivative size = 64, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5883, 5939, 5893, 30} \begin {gather*} -\frac {\cosh ^{-1}(a x)^2}{4 a^2}+\frac {1}{2} x^2 \cosh ^{-1}(a x)^2-\frac {x \sqrt {a x-1} \sqrt {a x+1} \cosh ^{-1}(a x)}{2 a}+\frac {x^2}{4} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x*ArcCosh[a*x]^2,x]

[Out]

x^2/4 - (x*Sqrt[-1 + a*x]*Sqrt[1 + a*x]*ArcCosh[a*x])/(2*a) - ArcCosh[a*x]^2/(4*a^2) + (x^2*ArcCosh[a*x]^2)/2

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 5883

Int[((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))^(n_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*ArcC
osh[c*x])^n/(d*(m + 1))), x] - Dist[b*c*(n/(d*(m + 1))), Int[(d*x)^(m + 1)*((a + b*ArcCosh[c*x])^(n - 1)/(Sqrt
[1 + c*x]*Sqrt[-1 + c*x])), x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] && NeQ[m, -1]

Rule 5893

Int[((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))^(n_.)/(Sqrt[(d1_) + (e1_.)*(x_)]*Sqrt[(d2_) + (e2_.)*(x_)]), x_Symbol]
:> Simp[(1/(b*c*(n + 1)))*Simp[Sqrt[1 + c*x]/Sqrt[d1 + e1*x]]*Simp[Sqrt[-1 + c*x]/Sqrt[d2 + e2*x]]*(a + b*Arc
Cosh[c*x])^(n + 1), x] /; FreeQ[{a, b, c, d1, e1, d2, e2, n}, x] && EqQ[e1, c*d1] && EqQ[e2, (-c)*d2] && NeQ[n
, -1]

Rule 5939

Int[((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_)*((d1_) + (e1_.)*(x_))^(p_)*((d2_) + (e2_.)*(x_
))^(p_), x_Symbol] :> Simp[f*(f*x)^(m - 1)*(d1 + e1*x)^(p + 1)*(d2 + e2*x)^(p + 1)*((a + b*ArcCosh[c*x])^n/(e1
*e2*(m + 2*p + 1))), x] + (Dist[f^2*((m - 1)/(c^2*(m + 2*p + 1))), Int[(f*x)^(m - 2)*(d1 + e1*x)^p*(d2 + e2*x)
^p*(a + b*ArcCosh[c*x])^n, x], x] - Dist[b*f*(n/(c*(m + 2*p + 1)))*Simp[(d1 + e1*x)^p/(1 + c*x)^p]*Simp[(d2 +
e2*x)^p/(-1 + c*x)^p], Int[(f*x)^(m - 1)*(1 + c*x)^(p + 1/2)*(-1 + c*x)^(p + 1/2)*(a + b*ArcCosh[c*x])^(n - 1)
, x], x]) /; FreeQ[{a, b, c, d1, e1, d2, e2, f, p}, x] && EqQ[e1, c*d1] && EqQ[e2, (-c)*d2] && GtQ[n, 0] && IG
tQ[m, 1] && NeQ[m + 2*p + 1, 0]

Rubi steps

\begin {align*} \int x \cosh ^{-1}(a x)^2 \, dx &=\frac {1}{2} x^2 \cosh ^{-1}(a x)^2-a \int \frac {x^2 \cosh ^{-1}(a x)}{\sqrt {-1+a x} \sqrt {1+a x}} \, dx\\ &=-\frac {x \sqrt {-1+a x} \sqrt {1+a x} \cosh ^{-1}(a x)}{2 a}+\frac {1}{2} x^2 \cosh ^{-1}(a x)^2+\frac {\int x \, dx}{2}-\frac {\int \frac {\cosh ^{-1}(a x)}{\sqrt {-1+a x} \sqrt {1+a x}} \, dx}{2 a}\\ &=\frac {x^2}{4}-\frac {x \sqrt {-1+a x} \sqrt {1+a x} \cosh ^{-1}(a x)}{2 a}-\frac {\cosh ^{-1}(a x)^2}{4 a^2}+\frac {1}{2} x^2 \cosh ^{-1}(a x)^2\\ \end {align*}

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Mathematica [A]
time = 0.04, size = 58, normalized size = 0.91 \begin {gather*} \frac {a^2 x^2-2 a x \sqrt {-1+a x} \sqrt {1+a x} \cosh ^{-1}(a x)+\left (-1+2 a^2 x^2\right ) \cosh ^{-1}(a x)^2}{4 a^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x*ArcCosh[a*x]^2,x]

[Out]

(a^2*x^2 - 2*a*x*Sqrt[-1 + a*x]*Sqrt[1 + a*x]*ArcCosh[a*x] + (-1 + 2*a^2*x^2)*ArcCosh[a*x]^2)/(4*a^2)

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Maple [A]
time = 1.64, size = 58, normalized size = 0.91

method	result	size
derivativedivides	\(\frac {\frac {a^{2} x^{2} \mathrm {arccosh}\left (a x \right )^{2}}{2}-\frac {a x \,\mathrm {arccosh}\left (a x \right ) \sqrt {a x -1}\, \sqrt {a x +1}}{2}-\frac {\mathrm {arccosh}\left (a x \right )^{2}}{4}+\frac {a^{2} x^{2}}{4}}{a^{2}}\)	\(58\)
default	\(\frac {\frac {a^{2} x^{2} \mathrm {arccosh}\left (a x \right )^{2}}{2}-\frac {a x \,\mathrm {arccosh}\left (a x \right ) \sqrt {a x -1}\, \sqrt {a x +1}}{2}-\frac {\mathrm {arccosh}\left (a x \right )^{2}}{4}+\frac {a^{2} x^{2}}{4}}{a^{2}}\)	\(58\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*arccosh(a*x)^2,x,method=_RETURNVERBOSE)

[Out]

1/a^2*(1/2*a^2*x^2*arccosh(a*x)^2-1/2*a*x*arccosh(a*x)*(a*x-1)^(1/2)*(a*x+1)^(1/2)-1/4*arccosh(a*x)^2+1/4*a^2*
x^2)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arccosh(a*x)^2,x, algorithm="maxima")

[Out]

1/2*x^2*log(a*x + sqrt(a*x + 1)*sqrt(a*x - 1))^2 - integrate((a^3*x^4 + sqrt(a*x + 1)*sqrt(a*x - 1)*a^2*x^3 -
a*x^2)*log(a*x + sqrt(a*x + 1)*sqrt(a*x - 1))/(a^3*x^3 + (a^2*x^2 - 1)*sqrt(a*x + 1)*sqrt(a*x - 1) - a*x), x)

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Fricas [A]
time = 0.33, size = 73, normalized size = 1.14 \begin {gather*} \frac {a^{2} x^{2} - 2 \, \sqrt {a^{2} x^{2} - 1} a x \log \left (a x + \sqrt {a^{2} x^{2} - 1}\right ) + {\left (2 \, a^{2} x^{2} - 1\right )} \log \left (a x + \sqrt {a^{2} x^{2} - 1}\right )^{2}}{4 \, a^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arccosh(a*x)^2,x, algorithm="fricas")

[Out]

1/4*(a^2*x^2 - 2*sqrt(a^2*x^2 - 1)*a*x*log(a*x + sqrt(a^2*x^2 - 1)) + (2*a^2*x^2 - 1)*log(a*x + sqrt(a^2*x^2 -
1))^2)/a^2

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Sympy [A]
time = 0.13, size = 60, normalized size = 0.94 \begin {gather*} \begin {cases} \frac {x^{2} \operatorname {acosh}^{2}{\left (a x \right )}}{2} + \frac {x^{2}}{4} - \frac {x \sqrt {a^{2} x^{2} - 1} \operatorname {acosh}{\left (a x \right )}}{2 a} - \frac {\operatorname {acosh}^{2}{\left (a x \right )}}{4 a^{2}} & \text {for}\: a \neq 0 \\- \frac {\pi ^{2} x^{2}}{8} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*acosh(a*x)**2,x)

[Out]

Piecewise((x**2*acosh(a*x)**2/2 + x**2/4 - x*sqrt(a**2*x**2 - 1)*acosh(a*x)/(2*a) - acosh(a*x)**2/(4*a**2), Ne
(a, 0)), (-pi**2*x**2/8, True))

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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arccosh(a*x)^2,x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,sageVARx):;OUTP
UT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int x\,{\mathrm {acosh}\left (a\,x\right )}^2 \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*acosh(a*x)^2,x)

[Out]

int(x*acosh(a*x)^2, x)

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